| A coin is tossed thrice. The probability that exactly two heads show up is |
A) \[\frac{1}{8}\]
B) \[\frac{2}{8}\]
C) \[\frac{3}{8}\]
D) \[\frac{4}{8}\]
Correct Answer: C
Solution :
| Possible outcomes are (HHH, HHT, HTH, THH, HTT, TTH, THT, TTT) |
| \[\therefore \] Total number of outcomes n (S) = 8 |
| Favourable outcomes are {HHT, HTH, THH} |
| Total favourable outcomes = 3 |
| \[\therefore \] Probability of getting two heads \[=\frac{3}{8}\] |
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