| The sum of five consecutive even numbers of set A is 220. What is the sum of a different set of five consecutive odd numbers whose second lowest number is 37 less than double of the lowest number of set A? |
A) 223
B) 225
C) 235
D) 243
E) None of these
Correct Answer: B
Solution :
| Let the first number be x. |
| \[\therefore \] \[x+x+2+x+4+x+6+x+8=220\] |
| \[\Rightarrow \] \[5x=220-20=200\] |
| \[\Rightarrow \] \[x=40\] |
| Second lowest number of different set |
| \[=40\times 2-37=43\] |
| Then, five consecutive numbers are 41, 43, 45, 47 and 49. |
| \[\therefore \] Their sum \[=41+43+45+47+49=225\] |
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