A is twice as good a workman as B and together they finish a piece of work in 14 days. The number of days taken by A alone to finish the work is |
A) 11
B) 21
C) 28
D) 42
Correct Answer: B
Solution :
(A's 1 day's work): (B's 1 day's work) = 2 : 1 |
(A + B)'s 1 day's work \[=\frac{1}{14}\] |
Divide \[=\frac{1}{14}\]in the ratio 2: 1 |
\[\therefore \] As 1 day's work \[=\left( \frac{1}{14}\times \frac{2}{3} \right)=\frac{1}{21}\] |
Hence, A alone can finish the work in 21 days. |
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