| Pradeep invested 20% more than Mohit. Mohit invested 10% less than Raghu. If the total sum of their investment is Rs. 17880, then how much amount did Raghu invest? [Corporation Bank (PO) 2011] |
A) Rs. 6000
B) Rs. 8000
C) Rs. 7000
D) Rs. 5000
E) None of these
Correct Answer: A
Solution :
| Let the amount Raghu invested be Rs. x |
| Then, amount invested by Mohit |
| \[=x\times \frac{90}{100}=\frac{9x}{10}\] |
| Now, amount invested by Pradeep |
| \[=\frac{9x}{10}\times \frac{120}{100}=\frac{108x}{100}=\frac{27x}{25}\] |
| \[\therefore \] \[x+\frac{9x}{10}+\frac{27x}{25}=17880\] |
| \[\Rightarrow \] \[\frac{50x+45x+54x}{50}=17880\] |
| \[\Rightarrow \] \[149x=17880\times 50\] |
| \[\Rightarrow \] \[x=\frac{894000}{149}\] |
| \[\therefore \] \[x=Rs.\,6000\] |
You need to login to perform this action.
You will be redirected in
3 sec
