A) \[{{65}^{o}}\]
B) \[{{35}^{o}}\]
C) \[{{125}^{o}}\]
D) \[{{60}^{o}}\]
Correct Answer: A
Solution :
[a] At 4:10, the hour hand is ahead of minute hand. |
Now, required angle is given by |
\[={{\left\{ \left( T-\frac{n}{5} \right)+\frac{n}{2} \right\}}^{o}}\] |
Here, \[T=4\], \[n=10\] |
\[=30\,\left( 4-\frac{10}{5} \right)+\frac{10}{2}\] |
\[=30\,(4-2)+5=60+5=65{}^\circ \] |
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