A) x+ y I z
B) \[x\times y\,\,|\,\,z\]
C) \[x,\,\,i\,\,y\,\,\phi \,\,z\]
D) \[x-y\,\,\phi \,\,z\]
Correct Answer: A
Solution :
| symbol and given interpretation | |||
| \[+\,\,\to \]greater than\[(>)\] | |||
| \[-\,\,\to \]not less than \[(\ge )\] | |||
| |\[\,\to \] less than \[(<)\] | |||
| \[\phi \to \]not greater than \[\,(\le )\] | |||
| \[\times \to \]equal to (=) and | |||
| i\[\to \]not equal (\[\ne \]) | |||
| Hence, statement \[x\,\,i\,\,y\,\,+\,\,z\Rightarrow x\ne y>z\] | |||
| Now, observing the options to check which of the given may be valid | |||
| Option | \[x>y\ne z\] | here,\[x>y\]which is possible because in the given statement (1)\[x\ne y\], although x can also be less than y and \[y\ne z\]is also followed in\[y\ne z\] | |
| Option | \[x=y<z\] | \[x=y\] is not possible because in statement (1) it say \[x\ne y\]. | |
| Option | \[x\ne y\le z\] | \[x\ne y\] is followed as in statement (1) but \[y\le z\] is not valid because \[y>z\] given in statement (1). | |
| Option | \[x\ge y\le z\] | \[x\ge y\] is not valid because statement (1) say \[x\ne y,\,\,y\le z\] not valid because statement (1) say \[y>z\] | |
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