A) 3
B) 1
C) 0
D) None of these
Correct Answer: A
Solution :
Sum of the digits of the 'super' number \[=1+2+3+...................+29\] \[=\frac{29}{2}.\{2\times 1+(29-1).1\}\] \[=\frac{29}{2}.(2+28)=\frac{29\times 30}{2}=29\times 15=435\] Thus \[x=7,\text{ }y=6\]You need to login to perform this action.
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