A) \[1:2\]
B) \[1:5\]
C) \[3:8\]
D) None of these
Correct Answer: D
Solution :
16 years ago, let T = x years and G = 8x years. After 8 years from now, \[T=(x+16+8)\]years and \[G=(8x+16+8)\]years. \[\therefore \] \[8x+24=3(x+24)\,\,\,\Rightarrow \,\,\,\,5x=48\] 8 years ago \[\frac{T}{G}=\frac{x\times 8}{8x+8}=\frac{\frac{48}{5}+8}{8\times \frac{48}{5}+8}=\frac{88}{424}=\frac{11}{53}\]You need to login to perform this action.
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