A) \[\frac{1}{2}hr\]
B) \[1\,hr\]
C) \[\frac{3}{4}hr\]
D) None of these
Correct Answer: B
Solution :
If new speed is \[\frac{a}{b}\]of original speed, then usual time \[\times \left( \frac{b}{a}-1 \right)=\] change in time \[\therefore \] usual time \[\times \left( \frac{4}{3}-1 \right)=\frac{1}{3}\] \[\Rightarrow \] usual time \[=\frac{1}{3}\times 3=1hr\]You need to login to perform this action.
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