A) kept unchanged
B) increased by 25%
C) increased by 20%
D) reduced by 20%
Correct Answer: D
Solution :
Let the original length and breadth be both 10 cm each. Then original area\[~=100\text{ }c{{m}^{2}}\] New length \[=10\times 1.25=12.5\,cm\] Let new breadth box. Then, \[12.5\,x=100\] \[\Rightarrow \] \[x=\frac{100}{12.5}=8\,cm\] Hence, % reduction in breadth \[=\frac{2}{10}\times 100=20%\]
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