A) \[3/20\]
B) \[1/6\]
C) \[1/5\]
D) \[1/3\]
Correct Answer: A
Solution :
Let total number of seats in the stadium be p; number of seats in the lower deck be x and number of seats in upper deck be y. \[\therefore \] \[p=x+y,\text{ }x=\text{ }p/4,\text{ }y=3p/4\] Now in the lower deck, \[4x/5\]seats were sold and \[x/5\]seats were unsold. No. of total seats sold in the stadium \[=2p/3.\] No. of unsold seats in the lower deck \[=x/5=\text{ }p/20\] No. of unsold seats in the stadium \[=p/3\] \[\therefore \] Required fraction \[=\frac{p/20}{p/3}=\frac{3}{20}\]You need to login to perform this action.
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