A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
Let \[{{f}_{1}}(x)={{x}^{3}}+m{{x}^{2}}-x+2m\] and \[{{f}_{2}}(x)={{x}^{2}}+mx-2\] Let \[m=1\] \[\therefore \] \[{{f}_{1}}(x)={{x}^{3}}+{{x}^{2}}-x+2\] and \[{{f}_{2}}(x)={{x}^{2}}+x-2=(x+2)\,\,(x-1)\] When \[x=1,\] \[f(1)=1+1-1+2\ne 0\] When \[x=-\text{ }2,\] \[f(-2)={{(-2)}^{3}}+{{(-2)}^{2}}-(-2)+2=0\] Required value of m is 1.You need to login to perform this action.
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