A) \[k=-1\]
B) \[k=2\]
C) \[k=3\]
D) \[k=-2\]
Correct Answer: C
Solution :
\[2x+ky+7=0\]\[\Rightarrow \]\[ky=-2x-7\]\[\Rightarrow \]\[y=\frac{-2}{k}x\frac{7}{k}\] \[27x+18y+25=0\] \[\Rightarrow \] \[18y=27x+25\] \[\Rightarrow \] \[y=\frac{3}{2}x+\frac{25}{18}\] \[\therefore \] \[\frac{-2}{k}\times \frac{3}{2}=1\,\,\Rightarrow \,\,k=3\]You need to login to perform this action.
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