A) \[22.22%\]
B) \[33.33%\]
C) \[44.44%\]
D) None of these
Correct Answer: B
Solution :
Let a packet of sugar marked 1 kg. Its actual weight is \[90%\] of 1000 gm = 900 gm Let C.P of each gm be Rs 1, Then C.P of this Packet = 900 gm S.P of this Packet \[=\text{ }120\text{ }%\]of C.P of 1 kg \[=\left( \frac{120}{100}\,\,\,\,1000 \right)=1200\] Therefore gain \[%=\left( \frac{300}{900}\,\,\,\,\,\,1000 \right)%\]You need to login to perform this action.
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