A) 35000
B) 40000
C) 30000
D) 36000
Correct Answer: C
Solution :
Let the original salaries of Ranjit and Sudha be Rs.3x and Rs.4x respectively. Then, \[\frac{3x+6000}{4x+6000}=\frac{15}{19}\] \[19(3x+6000)=15(4x+6000)\] \[57x\,+114000=60x+90000\] \[114000-90000=60x-3x\] \[3x=24000\] Shudha 's present salary =\[(3x=6000)\] \[=Rs.(24000+6000)=Rs.30000\]You need to login to perform this action.
You will be redirected in
3 sec