A) 200 min
B) 100 min
C) 110 min
D) 120 min
Correct Answer: A
Solution :
Work done by the third pipe in 1 min \[=\frac{1}{100}-\frac{1}{120}+\frac{1}{150}\] \[=\frac{1}{100}-\frac{3}{200}=\frac{1}{200}\] The third pipe alone can empty the cistern in 200 minYou need to login to perform this action.
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