A) \[\frac{2}{3}\]
B) \[\frac{2}{3}\]
C) \[\frac{3}{2}\]
D) \[\frac{3}{2}\]
Correct Answer: C
Solution :
\[p{{x}^{2}}+2x+3p=0\] Here, \[a=p,b=2,c=3p\] Some of the roots \[=\frac{-b}{a}=\frac{-2}{p}\]product of roots \[=\frac{c}{a}=\frac{3p}{p}\] Since sum of roots = product of roots \[\therefore \] \[\frac{-2}{p}=\frac{3p}{p}\]\[p=\frac{-2}{3}\]You need to login to perform this action.
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