A) 41.6
B) 42.6
C) 46.4
D) 36.4
E) None of these
Correct Answer: C
Solution :
Average marks of 52 students \[=52\times 80=4160\] When 10 students left the average will be\[42\times 88=3696\] Required average\[=\frac{4160-3696}{10}=\frac{464}{10}=46.4\]You need to login to perform this action.
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