A) 32
B) 64
C) 34
D) 68
Correct Answer: D
Solution :
[d] Let side of rhombus be x By Pythagorean Theorem, \[{{x}^{2}}={{(15)}^{2}}+{{(8)}^{2}}\] \[{{x}^{2}}=225+64=289\] \[\therefore x=\sqrt{289}=17\,\,cm\] \[\therefore \]Perimeter of rhombus \[=4\times \]side \[=4\times 17\] =68 cmYou need to login to perform this action.
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