A) 19
B) 20
C) 21
D) 23
Correct Answer: A
Solution :
[a] Let the numbers be x and y. \[\therefore x\,\,(x+y)=247\] \[and\,\,y\,\,(x+y)=114\] \[\Rightarrow {{x}^{2}}+xy=247\,\,and\,\,xy+{{y}^{2}}=114\] On adding; \[{{x}^{2}}+xy+xy+{{y}^{2}}=247+114\] \[\Rightarrow {{x}^{2}}+2xy+{{y}^{2}}=361\] \[\Rightarrow {{(x+y)}^{2}}={{19}^{2}}\Rightarrow x+y=19\]You need to login to perform this action.
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