A) \[27{}^\circ C\]
B) \[30{}^\circ C\]
C) \[32{}^\circ C\]
D) \[32.5{}^\circ C\]
Correct Answer: B
Solution :
[b] Time difference between 9.00 A.M & 2.00 P.M=5 hours Temperature difference between \[21{}^\circ C\text{ }\And \text{ }36{}^\circ C\] \[=36-\,21=15{}^\circ C\] Now, Time difference between 9.00 A.M & 12.00 Noon =3hrs. In 5 hours \[\xrightarrow[difference]{temperature}15{}^\circ C\] So, in 3 hours \[\xrightarrow[difference]{temperature}\left( \frac{15}{5}\times 3 \right)=9{}^\circ C\] So, temperature at noon =\[21+9=30{}^\circ C\]You need to login to perform this action.
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