A) 3
B) 1
C) 0
D) None of these
Correct Answer: A
Solution :
[a] Sum of the digits of the 'super' number \[=1+2+3+............+29\] \[=\frac{29}{2}.\left\{ 2\times 1+(29-\,1).1 \right\}\] \[=\frac{29}{2}.(2+28)=\frac{29\times 30}{2}=29\times 15=435\] Thus x=7, y=6You need to login to perform this action.
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