| In following series find 20th number |
| \[9,\,\,5,\,\,1,\,\,-3,\,\,-7,\,\,-11...\] |
A) \[-64\]
B) \[-75\]
C) \[-70\]
D) \[-67\]
Correct Answer: D
Solution :
[d] First term of A.P.=9 Common difference \[=-\,4\] So, 20th term \[{{T}_{20}}=A+(20-\,1)\,(D)\] \[=9+(20-1)\,\,(-4)\] \[=9-\,76\] \[=-\,67\]
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