A) 3000
B) 2980
C) 3050
D) 3180
Correct Answer: D
Solution :
[d] Here, P=12500 R=12% T= 2 years C.I=? \[\therefore \,\,C.I.=P\,\,{{\left( 1+\frac{r}{100} \right)}^{n}}-p\] \[=12500\,\,{{\left( 1+\frac{12}{100} \right)}^{2}}-12500\] \[=12500\times \frac{28}{25}\times \frac{28}{25}-\,12500\] \[=15680-\,12500=3180\] Compound interest =Rs. 3180You need to login to perform this action.
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