A) K=\[-\,1\]
B) k=2
C) K=3
D) k=\[-\,2\]
Correct Answer: C
Solution :
[c] \[2x+ky+7=0\Rightarrow ky=-\,2x-\,7\Rightarrow \] \[y=\frac{-\,2}{k}x-\,\frac{7}{k}\] \[27x+18y+25=0\Rightarrow 18y=27x+25\] \[\Rightarrow y=\frac{3}{2}x+\frac{25}{18}\] \[\therefore \frac{-2}{k}\times \frac{3}{2}=1\Rightarrow k=3\]You need to login to perform this action.
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