A) 4, 12, 12, 20
B) 5, 11, 13, 19
C) 6, 10, 14, 18
D) 9, 7, 15, 17
Correct Answer: C
Solution :
[c] Let four numbers are a, b, c, d, then a+b+c+d=48 ... (i) And a+5=b+1 ... (ii) Or, \[a=b-4\] ... (iii) And \[c-\,3=d-\,7\] ... (iv) \[c=d-4\] ... (v) Substituting equation (iii) and (v) in equation (i) we get \[b-\,4+b+d-\,4+d=48\] \[b+d=28\] But we know, \[b+1=d-\,7\] \[\therefore \,\,\,b=d-\,8\] Substituting in equation (vi) we get \[d-\,8\ne d=28\] d=18 Solving this way we get a\[6,\,\,b=10,\,\,c=14\,\,and\,\,d=18\]You need to login to perform this action.
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