A) Increase by 2
B) Increase by 1
C) Remain the same
D) Increase by 1.4
Correct Answer: B
Solution :
[b] Let the numbers be \[-2,\,\,n-1,\,\,n,\,\,n+1\] and n+2. Their average = n. Next two consecutive numbers are \[n+3\]and\[n+4\]. Therefore the average of 7 consecutive numbers \[=\frac{(n-\,2)+(n-\,1)+n+(n+1)+(n+2)+(n+3)+(n+4)}{7}\]\[=\frac{5n+2n+7}{7}=n+1\]You need to login to perform this action.
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