A) \[\frac{43}{220}\]
B) \[\frac{63}{220}\]
C) \[\frac{43}{110}\]
D) \[\frac{1}{11}\]
E) \[\frac{2}{23}\]
Correct Answer: B
Solution :
Total no, of events in sample space \[=n(S){{=}^{12}}{{C}_{3}}=220\] \[n(E){{=}^{7}}{{C}_{2}}{{\times }^{3}}{{C}_{1}}=63\] \[\therefore \] \[P(E)=\frac{n(E)}{n(S)}=\frac{63}{220}\]You need to login to perform this action.
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