A) 8, 9, 8
B) 9, 8, 8
C) 10, 1, 6
D) 10, 8, 9
Correct Answer: C
Solution :
Least number = z \[x=13\times 1+8=21\] \[y=11x+9=11\times 21+9=240\] \[z=9y+8=9\times 240+8=2168\] Dividing 2168 by 13, 11, 9. We get the remainders = 10, 1, 6You need to login to perform this action.
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