A) \[50{}^\circ \]
B) \[65{}^\circ \]
C) \[70{}^\circ \]
D) \[75{}^\circ \]
Correct Answer: B
Solution :
Quadrilateral PQOR is cyclic. \[\therefore \]\[\angle QOR=180{}^\circ -\angle RPQ\] \[=180{}^\circ -50{}^\circ =130{}^\circ \] Now,\[\angle QOR=2\,\,\angle QSR\] \[\therefore \]\[\angle QSR=\frac{130{}^\circ }{2}=65{}^\circ \]You need to login to perform this action.
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