A) 1
B) \[\frac{3}{4}\]
C) 0
D) 21
Correct Answer: C
Solution :
\[\sin \,B\,\,=\,\,\frac{1}{2}\] Then, \[\cos B=\sqrt{1-{{\sin }^{2}}B}=\sqrt{1-{{\left( \frac{1}{2} \right)}^{2}}}=\frac{\sqrt{3}}{2}\] \[\therefore \] . \[\,=\frac{3\sqrt{3}}{2}-\frac{4\times 3\sqrt{3}}{8}\] \[=\frac{3\sqrt{3}}{2}-\frac{3\sqrt{3}}{12}=0\]You need to login to perform this action.
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