A) 8, 9
B) 7, 6
C) 12, 6
D) 7, 10
Correct Answer: A
Solution :
In any quadrilateral ABCD, when diagonal intersect at O, then \[\frac{AO}{OC}=\frac{OD}{OB}\] \[\frac{AO}{OC}=\frac{OD}{OB}\Rightarrow \frac{3}{x-2}=\frac{x-5}{3x-19}\] \[\Rightarrow \]\[3(3x-19)=(x-3)(x-5)\] \[\Rightarrow \]\[9x-57={{x}^{2}}-8x+15\] \[\Rightarrow \]\[{{x}^{2}}-17x+72=0\] On solving,\[(x-8)(x-9)=0\,\,\,\,\Rightarrow \,\,x=8,9\]You need to login to perform this action.
You will be redirected in
3 sec