A) 2
B) 12
C) 10
D) 11
Correct Answer: D
Solution :
\[\because x-\frac{1}{x}=3\] On square both the Side. \[{{\left( x-\frac{1}{x} \right)}^{2}}={{(3)}^{2}}\] \[\Rightarrow \] \[{{x}^{2}}+\frac{1}{{{x}^{2}}}-2\cdot x\cdot \frac{1}{x}=9\] \[\therefore \] \[{{x}^{2}}+\frac{1}{{{x}^{2}}}=9+2=11\]You need to login to perform this action.
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