A) 12 cm
B) 9 cm
C) 15 cm
D) 8 cm
Correct Answer: C
Solution :
Let ABCD be a rhombus in which diagonals AC =24 cm and BD =18 cm. We know that, the diagonals of a rhombus bisect each other at right angles. \[\therefore \]\[OA=\frac{1}{2}AC=\left( \frac{1}{2}\times 24 \right)=12\,\,cm\] \[OB=\frac{1}{2}BD=\left( \frac{1}{2}\times 18 \right)=9\,\,cm\] \[A{{B}^{2}}=O{{A}^{2}}+O{{B}^{2}}={{(12)}^{2}}+{{9}^{2}}\] \[=144+81=225\] \[\Rightarrow \]\[AB=\sqrt{225}=15\,\,cm\] \[\therefore \]Each side of the rhombus is 15 cm.You need to login to perform this action.
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