A) \[\frac{xyz}{3abc}\]
B) \[3\,xyzabc\]
C) \[\frac{3xyz}{abc}\]
D) \[\frac{xyz}{abc}\]
Correct Answer: C
Solution :
\[\frac{x}{a}=b-c;\,\,\frac{y}{b}=c-a;\,\,\frac{z}{c}=a-b\] Again,\[b-c+c-a+a-b=0\] \[\therefore \] \[{{\left( \frac{x}{a} \right)}^{3}}+{{\left( \frac{y}{b} \right)}^{3}}+{{\left( \frac{z}{c} \right)}^{3}}\] \[={{(b-c)}^{3}}+{{(c-a)}^{3}}+{{(a-b)}^{3}}\] \[=3(b-c)(c-a)(a-b)=\frac{3xyz}{abc}\]You need to login to perform this action.
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