A) \[\frac{1}{2}\]
B) \[\sqrt{3}\]
C) 1
D) 2
Correct Answer: C
Solution :
\[{{\sin }^{2}}38{}^\circ +{{\cos }^{2}}38{}^\circ \] \[={{\sin }^{2}}38{}^\circ +\left( 1-{{\sin }^{2}}38{}^\circ \right)=1\]You need to login to perform this action.
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