A) 2
B) 9
C) 3
D) 5
Correct Answer: B
Solution :
\[\left| \div =-\left| \times =+\left| +=\div \left| -=\times \right. \right. \right. \right.\] \[10\div 3\times 4+2-1\] After interchange the signs \[10-3+4\div 2\times 1\] \[=\,10-3+\frac{4}{2}\times 1\] \[=10-3+2\] \[=12-3=9\]You need to login to perform this action.
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