A) 0
B) \[\frac{4097}{64}\]
C) 1
D) \[\frac{16}{4097}\]
Correct Answer: B
Solution :
\[{{(16)}^{\frac{3}{2}}}+{{16}^{-\frac{3}{2}}}={{4}^{3}}+\frac{1}{{{4}^{3}}}=64+\frac{1}{64}\] \[=\frac{4096+1}{64}=\frac{4097}{64}\]You need to login to perform this action.
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