A) 12
B) 20
C) 24
D) 48
Correct Answer: D
Solution :
Let second number = x \[\therefore \] First number = 2x and third number = 4x According to question, \[56=\frac{2x+x+4x}{3}\] \[\Rightarrow \] \[x=\frac{56\times 3}{7}=24\] \[\therefore \] Required difference \[=4x-2x\] \[\,=2x=2\times 24=48\]You need to login to perform this action.
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