A) 40%
B) 38%
C) 33%
D) 43%
Correct Answer: C
Solution :
Maximum marks = x, then Given, pas marks \[=x\times \frac{30}{100}+15\] \[=x\times \frac{40}{100}-35\Rightarrow 3x+150=4x-350\] \[\therefore \,\] \[x=150+350=500\] \[\therefore \] Pass marks \[=500\times \frac{3}{10}+15=165\] \[\therefore \] Necessary percentage for passing \[=\frac{165}{500}\times 100=33%\]You need to login to perform this action.
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