Answer:
Since, AD BC and AB is the transversal ...(i) (1)
[coinheritor angle]
Similarly, since
and
is the transversal
[coinheritor angles] ...(ii) (1)
From Eqs. (i) and (ii), we get
(1)
OR
In
we have exterior
[exterior angle of a triangle is equal to the sum of two interior opposite angles] (1)
exterior
(given)
exterior
is bisected by
(1)
But these are alternate interior angles formed when, the transversal AC cuts the line AE and BC.
(1)
Hence proved.
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