is
exactly divisible by x2 - 1 i.e. (x - 1) (x + 1)
i.e.
and 
i.e.
Adding, we get 
Subtracting, we get 
(a)
holds.
Answer:
is
exactly divisible by (x2 - 1). Then the values of 'a' and 'b' are
(a) 
(b)
(c) 
(d)
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