Answer:
Let a be odd.
= 4 (An integer) + 1 or 3 = 4m + 1 or 4m + 3 where m is an
integer
Let a be even
[ any
odd integer divided by 4 will have remainder 1 or 3]
a
= 2q
a3
= 8q3 = 4 (2q3) = 4(m), m = 2q3 is an integer
a3
is of the form 4m or 4m + 1 or 4/K + 3 where m is some positive integer.
OR
Let if possible be a
rational number
where p
and q are co-prime integers and
irrational number = rational
number, which is not possible
Hence our supposition is wrong. is an
irrational number
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