Answer:
Since D and E are mid points of the sides BC and CA respectively of
DE
||BA
Similarly FE || BC and DF || CA
AFDE
is a || gm and BDEF is a || gm
Now in and
[Opposite
angles of || gm AFDE]
[Opposite
angles of || gm BDEF]
[By AA
rule of similarity]
Hence
area area
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