Answer:
Mass of solute volume x
density
=
0.6 x 1.06
=
0.636 g
Mass of solvent (water) = volume
x density
=
1000 x 1
= 1000
(molar
mass of solute) = 60 g mol 1
(depression
in freezing point) = 0.0205°
(molal
depression constant of water)
i = van't Hoff factor
= [1 + ( y ? 1 ) x ] = ( 1 + x )
y = total number of ions from 1 unit of solute
x = degree of ionisation
= 1.04
Thus, i = (1 + x) = 1.04
x
= 0.04 [1]
By Ostwald's dilution law for weak acid
where, C = molar concentration of
()
[1]
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