A) \[\operatorname{r}\,-\,\,\left( 3p\times 2q \right)=r\,-6pq\] [binomial]
B) \[\operatorname{r}\,-\,\,\left( 3p\times 2q \right)=r\,-8pq\] [binomial]
C) \[\operatorname{r}\,-\,\,\left( 3p\times 2q \right)=r\,-7pq\] [binomial]
D) \[\operatorname{r}\,-\,\,\left( 2p\times 2q \right)=r\,-7pq\] [binomial]
Correct Answer: A
Solution :
\[\operatorname{r}\,-\,\,\left( 3p\times 2q \right)=r\,-6pq\] [binomial]You need to login to perform this action.
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