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Banking Sample Paper SBI Clerk Grade (Main) Sample Test Paper-2

  • question_answer
    The sum of scores of A and B is 1624. \[\frac{\text{7}}{\text{12}}\text{th}\] of A's score is equal to \[\frac{\text{5}}{\text{8}}\text{th}\] of B's score. By what percent has A scored more than that of B?

    A)  \[4\frac{2}{3}\]                        

    B)  \[7\frac{2}{5}\]            

    C)         \[5\frac{2}{5}\]                        

    D)  \[7\frac{1}{7}\]

    E)         \[5\frac{4}{7}\]

    Correct Answer: D

    Solution :

     A+B= 1624                 ?..(i) Again, \[\frac{7A}{12}=\frac{5B}{8}\] \[\Rightarrow \,\,\frac{7A}{3}=\frac{5B}{2}\] \[\Rightarrow \,\,A=\frac{3}{7}\times \frac{5}{2}\,\,\,\,B=\frac{15}{14}\,\,\,B\] \[\therefore \,\frac{15B}{14}+B=1624\] \[\Rightarrow \frac{15B+14B}{14}=1624\] \[\Rightarrow 29B=14\times 1624\] \[\Rightarrow B=\frac{14\times 1624}{29}=784\] \[\therefore A=1624-784=840\]  [From equation (i)] \[\therefore \] Required percent \[\left( \frac{840-784}{784} \right)\times 100\] \[=\frac{56}{784}\times 100=\frac{50}{7}=7\frac{1}{7}\]


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