A) 64
B) 36
C) \[\sqrt{6}\]
D) 6
E) None of these
Correct Answer: D
Solution :
\[{{(?)}^{3}}=\sqrt{2.25}\times {{12}^{2}}\] \[=1.5\times 144=216={{6}^{3}}\] \[\therefore ?=6\]You need to login to perform this action.
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