A) 42 kgs
B) 40 kgs
C) 36 kgs
D) 34 kgs
E) 38 kgs
Correct Answer: E
Solution :
\[C=(A+24)kg\] \[C=(B-3)kg\] \[\therefore \]\[A+24=B-3\Rightarrow B=A+27\] \[\therefore \]\[A+B+C=40\times 3\] \[\Rightarrow \]\[A+A+27+A+24=120\] \[\Rightarrow \]\[3A+51=120\] \[\Rightarrow \]\[3A=120-51=69\] \[\Rightarrow \]\[A=\frac{69}{3}=23kg\] \[B=A+27=23+27=50kg\] \[C=120-23-50=47kg\] \[D=47-15=32kg\] \[\therefore \]Required average weight \[=\frac{23+50+47+32}{4}\] \[=\frac{23+50+47+32}{4}\]You need to login to perform this action.
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