Direction: What should come in place of the question mark (?) in the question? |
A) \[{{(12)}^{2}}\]
B) \[\sqrt{12}\]
C) \[2\sqrt{12}\]
D) \[-\sqrt{12}\]
E) 12
Correct Answer: E
Solution :
\[{{(?)}^{2}}=\frac{54.4\times 5\times 8}{16}+8\] \[=136+8=144\] \[\therefore \]\[?=\sqrt{144}=\pm 12\]You need to login to perform this action.
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